MIME-Version: 1.0 Content-Type: multipart/related; boundary="----=_NextPart_01C9D987.BA950330" This document is a Web archive file. If you are seeing this message, this means your browser or editor doesn't support Web archive files. For more information on the Web archive format, go to http://officeupdate.microsoft.com/office/webarchive.htm ------=_NextPart_01C9D987.BA950330 Content-Location: file:///C:/CD29D1D5/sample123-5.htm Content-Transfer-Encoding: quoted-printable Content-Type: text/html; charset="us-ascii" Test 1 Math 113

Test  5 Sample Math 123 a=

 

1. Split the fraction up into separate terms and simplify each term if possible.  If it is not possib= le, state so.


2. Use long division t= o find the quotiet and remainder.


3. Expand and simplify=

 A.   3x( 4x – 2) – (6 – 5x)        =             &nb= sp;    B.  (2x –5)(x+2) – (x–1)(3x+2)

Ans:12x2 – x – 6        =             &nb= sp;            =        Ans:–x2 – 8<= /o:p>

4.  Factor completely.  If it is not factorable, state so:=

A. 3X + 15Y        =             &nb= sp;            =            B. 25x2y2= –15x2y3= + 40x3 y2=  

Ans:3(x + 5y)        =             &nb= sp;            =           Ans: 5x2y2(5 – 3y + 8x)

C.  3xa –2ya + 3xb - 2yb        =                =  D.  4x2= – 9

Ans: (3x – 2y)(a + b)        =             &nb= sp;          Ans: (2x + 3)(2x – 3)

E.  ax 4 – 16a        =             &nb= sp;            =           F. x2 –5x – 6

Ans: a(x2 + 4)(x +2)(x –2)        =             &nb= sp;  Ans: (x – 6)(x + 1)

G.  x2 – 15x&= nbsp; + 36        =             &nb= sp;            =    H.  y2 + 16

Ans: (x – 12)(x – 3)        =             &nb= sp;          =  Ans: prime       

I.  2x2 – 5x&n= bsp; + 2        =             &nb= sp;            =        J. x2 – 5x  + 2

Ans: (2x – 1)(x –2)        =             &nb= sp;          =    Ans: prime

K. 6x2 – 25x  + 4        =             &nb= sp;            =     L. – x2 – x  + 2

Ans: (6x – 1)(x – 4)        =             &nb= sp;         =    Ans: &#= 8211;(x – 1)(x + 2)

 

5.  Factor completely.  If it is not factorable, state so:=

A. 50x3y4 – 35x2y3 += 45x4y3<= span style=3D'mso-spacerun:yes'>        =            B.  25x2 – 36 =

Ans: 5x2y2(10xy – = 7 + 9x2)        =              Ans: (5x – 6)(5x + 6)

C.   x 4 – 16        =             &nb= sp;            =              D.  x2 + 5x – 6

Ans: (x + 2)(x – 2)(x2 + 4)        =             =    Ans: (x= – 1)(x + 6)

E.  x2 – 9x – 36        =             &nb= sp;            =        F.  4y2 + 9

Ans: (x + 12)(x – 3)        =             =            =  Ans: prime       

G.  3x2 – 5x – 2<= span style=3D'mso-spacerun:yes'>        =             &nb= sp;            =       H. –6x2 + 25x – 4

Ans: (3x + 1)(x – 2)                =             =    Ans: &#= 8211;(6x – 1)(x – 4)        =             &nb= sp;            =       

I.  x2 – 2xy – 3= y2 

Ans: (x + y)(x – 3y)        =                   =             &nb= sp;   

J.  Factor 8x3 – 1        =             &nb= sp;            =      K. Factor  27A6 + 8        =             &nb= sp;

Ans: (2x – 1)(4x2 + 2x + 1)        =             =  Ans: (3A2 + 2)(9A4 – 6A2 + 4)

6.  Solve the following equations.

A.   4y2 – 9 =3D 5y        =             &nb= sp;            =         B.  x (2x – 3) = =3D x + 6

Ans: x =3D 9/4, –1         =             &nb= sp;            =        Ans: x =3D 3, –1

7.  We have four identical sticks with length of x ft.  We cut off 3 = ft from two of them and use them as the width of a rectangular wooden frame. W= e attached an extra 5-ft piece to each of the other two sticks and use them as the len= gth of the rectangular wooden frame.  If the area that is enclosed by this frame is 84 ft2 , what is the length of = the original sticks?       Ans: 9 ft        =  

 

8.  The height of a trian= gle is 5 more than the base.  The = area of the triangle is 12 ft2.  Find the base and height of triangle. Ans: Base =3D 3ft, ht =3D 8 ft

 

9. Given that the height h of a thrown object after t seconds is h =3D<= span style=3D'font-size:12.0pt;mso-bidi-font-size:10.0pt'> vt – 16t2 where v is the initial velocity.  Find the time it will take for the object to hit the ground if the initial velocity is 48 ft/sec.              =             &nb= sp;            =             &nb= sp;            =             &nb= sp;            =      

 Ans: 3 = sec.        =             &nb= sp;            =             &nb= sp;            =             &nb= sp;            =   

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