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Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4) 
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Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4
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Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
------=_NextPart_01C8D7F8.DB4BAC50 Content-Location: file:///C:/7102A2B3/2AdditionandSubtractionofSignedNumbers_files/slide0144.htm Content-Transfer-Encoding: quoted-printable Content-Type: text/html; charset="us-ascii" Addition and Subtraction of Signed Numbers
Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
b.  3 – (–7)  
------=_NextPart_01C8D7F8.DB4BAC50 Content-Location: file:///C:/7102A2B3/2AdditionandSubtractionofSignedNumbers_files/slide0145.htm Content-Transfer-Encoding: quoted-printable Content-Type: text/html; charset="us-ascii" Addition and Subtraction of Signed Numbers
Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
b.  3 – (–7)   ß remove “(   )”, change to opposit= e
  =3D 3 + 7
------=_NextPart_01C8D7F8.DB4BAC50 Content-Location: file:///C:/7102A2B3/2AdditionandSubtractionofSignedNumbers_files/slide0146.htm Content-Transfer-Encoding: quoted-printable Content-Type: text/html; charset="us-ascii" Addition and Subtraction of Signed Numbers
Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
b.  3 – (–7)   ß remove “(   )”, change to opposit= e
  =3D 3 + 7 =3D 10
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Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
b.  3 – (–7)   ß remove “(   )”, change to opposit= e
  =3D 3 + 7 =3D 10
c. –12 – (–5) 
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Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
b.  3 – (–7)   ß remove “(   )”, change to opposit= e
  =3D 3 + 7 =3D 10
c. –12 – (–5)  ß remove “(   )̶= 1;, change to opposite
  =3D –12 + 5
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Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
b.  3 – (–7)   ß remove “(   )”, change to opposit= e
  =3D 3 + 7 =3D 10
c. –12 – (–5)  ß remove “(   )̶= 1;, change to opposite
  =3D –12 + 5 =3D –7  
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Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
b.  3 – (–7)   ß remove “(   )”, change to opposit= e
  =3D 3 + 7 =3D 10
c. –12 – (–5)  ß remove “(   )̶= 1;, change to opposite
  =3D –12 + 5 =3D –7  
Summary for removing parentheses for addition and subtraction of signed numbers:
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Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
b.  3 – (–7)   ß remove “(   )”, change to opposit= e
  =3D 3 + 7 =3D 10
c. –12 – (–5)  ß remove “(   )̶= 1;, change to opposite
  =3D –12 + 5 =3D –7  
Summary for removing parentheses for addition and subtraction of signed numbers:
 
For addition:        a + (+b) =3D= a + b        = ;    a + <= /span>(–b) =3D= a – b
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Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
b.  3 – (–7)   ß remove “(   )”, change to opposit= e
  =3D 3 + 7 =3D 10
c. –12 – (–5)  ß remove “(   )̶= 1;, change to opposite
  =3D –12 + 5 =3D –7  
Summary for removing parentheses for addition and subtraction of signed numbers:
 
For addition:        a + (+b) =3D= a + b        = ;    a + <= /span>(–b) =3D= a – b
For subtraction:    a &= #8211; (+b) =3D a – b        = ;    a – (–b)  = =3D a + b
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Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
b.  3 – (–7)   ß remove “(   )”, change to opposit= e
  =3D 3 + 7 =3D 10
c. –12 – (–5)  ß remove “(   )̶= 1;, change to opposite
  =3D –12 + 5 =3D –7  
Summary for removing parentheses for addition and subtraction of signed numbers:
 
For addition:        a + (+b) =3D= a + b        = ;    a + <= /span>(–b) =3D= a – b
For subtraction:    a &= #8211; (+b) =3D a – b        = ;    a – (–b)  = =3D a + b
Example C : Remove the parentheses then combine.&= nbsp;
a.  –6 – (–8) ̵= 1; (–2) – (9)      
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Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
b.  3 – (–7)   ß remove “(   )”, change to opposit= e
  =3D 3 + 7 =3D 10
c. –12 – (–5)  ß remove “(   )̶= 1;, change to opposite
  =3D –12 + 5 =3D –7  
Summary for removing parentheses for addition and subtraction of signed numbers:
 
For addition:        a + (+b) =3D= a + b        = ;    a + <= /span>(–b) =3D= a – b
For subtraction:    a &= #8211; (+b) =3D a – b        = ;    a – (–b)  = =3D a + b
Example C : Remove the parentheses then combine.&= nbsp;
a.  –6 – (–8) ̵= 1; (–2) – (9)       rem= ove “(  )”
  =3D –6   + 8     + 2     – 9 
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Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
b.  3 – (–7)   ß remove “(   )”, change to opposit= e
  =3D 3 + 7 =3D 10
c. –12 – (–5)  ß remove “(   )̶= 1;, change to opposite
  =3D –12 + 5 =3D –7  
Summary for removing parentheses for addition and subtraction of signed numbers:
 
For addition:        a + (+b) =3D= a + b        = ;    a + <= /span>(–b) =3D= a – b
For subtraction:    a &= #8211; (+b) =3D a – b        = ;    a – (–b)  = =3D a + b
Example C : Remove the parentheses then combine.&= nbsp;
a.  –6 – (–8) ̵= 1; (–2) – (9)       rem= ove “(  )”
  =3D –6   + 8     + 2     – 9       
  =3D  8 + 2 – 6 – 9 
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Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
b.  3 – (–7)   ß remove “(   )”, change to opposit= e
  =3D 3 + 7 =3D 10
c. –12 – (–5)  ß remove “(   )̶= 1;, change to opposite
  =3D –12 + 5 =3D –7  
Summary for removing parentheses for addition and subtraction of signed numbers:
 
For addition:        a + (+b) =3D= a + b        = ;    a + <= /span>(–b) =3D= a – b
For subtraction:    a &= #8211; (+b) =3D a – b        = ;    a – (–b)  = =3D a + b
Example C : Remove the parentheses then combine.&= nbsp;
a.  –6 – (–8) ̵= 1; (–2) – (9)       rem= ove “(  )”
  =3D –6   + 8     + 2     – 9       
  =3D  8 + 2 – 6 – 9  =3D 10 – 15 
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Addition and Subtraction of Signed Numbers
Example B. Remove parentheses then combine.
<= span style=3D'font-size:133%;color:#006600'>a.  5 – (+4)  ß remove “(   )”, change to opposit= e        = ;        
  =3D 5 – 4 =3D 1
b.  3 – (–7)   ß remove “(   )”, change to opposit= e
  =3D 3 + 7 =3D 10
c. –12 – (–5)  ß remove “(   )̶= 1;, change to opposite
  =3D –12 + 5 =3D –7  
Summary for removing parentheses for addition and subtraction of signed numbers:
 
For addition:        a + (+b) =3D= a + b        = ;    a + <= /span>(–b) =3D= a – b
For subtraction:    a &= #8211; (+b) =3D a – b        = ;    a – (–b)  = =3D a + b
Example C : Remove the parentheses then combine.&= nbsp;
a.  –6 – (–8) ̵= 1; (–2) – (9)       rem= ove “(  )”
  =3D –6   + 8     + 2     – 9       
  =3D  8 + 2 – 6 – 9  =3D 10 – 15  =3D  –5
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b. 2 + (–4) – (–= 8) – (5) + (–9 )    
Addition and Subtraction of Signed Numbers
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9  <= /span>
Addition and Subtraction of Signed Numbers
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9
Addition and Subtraction of Signed Numbers
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9 &n= bsp;
=3D 10 – 18
Addition and Subtraction of Signed Numbers
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9 &n= bsp;
=3D 10 – 18
=3D –8        = ;            &n= bsp;          
Addition and Subtraction of Signed Numbers
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9 &n= bsp;
=3D 10 – 18
=3D –8        = ;            &n= bsp;          
Addition and Subtraction of Signed Numbers
The (   ), [   ], or {   } are grouping symbols.
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9 &n= bsp;
=3D 10 – 18
=3D –8        = ;            &n= bsp;          
Addition and Subtraction of Signed Numbers
The (   ), [   ], or {   } are grouping symbols. Eac= h set of symbol must contain both the left-hand and right-hand parts.
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9 &n= bsp;
=3D 10 – 18
=3D –8        = ;            &n= bsp;          
Addition and Subtraction of Signed Numbers
The (   ), [   ], or {   } are grouping symbols. Eac= h set of symbol must contain both the left-hand and right-hand parts. Each set encloses calculations that are to be done within the symbol.
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9 &n= bsp;
=3D 10 – 18
=3D –8        = ;            &n= bsp;          
Addition and Subtraction of Signed Numbers
The (   ), [   ], or {   } are grouping symbols. Eac= h set of symbol must contain both the left-hand and right-hand parts. Each set encloses calculations that are to be done within the symbol.
Example D :
a. –6 – (8 – 9)     
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9 &n= bsp;
=3D 10 – 18
=3D –8        = ;            &n= bsp;          
Addition and Subtraction of Signed Numbers
The (   ), [   ], or {   } are grouping symbols. Eac= h set of symbol must contain both the left-hand and right-hand parts. Each set encloses calculations that are to be done within the symbol.
Example D :
a. –6 – (8 – 9)      do the calculation inside the “(  )”
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9 &n= bsp;
=3D 10 – 18
=3D –8        = ;            &n= bsp;          
Addition and Subtraction of Signed Numbers
The (   ), [   ], or {   } are grouping symbols. Eac= h set of symbol must contain both the left-hand and right-hand parts. Each set encloses calculations that are to be done within the symbol.
Example D :
a. –6 – (8 – 9)      do the calculation inside the “(  )”
=3D – 6 – (– 1)       
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9 &n= bsp;
=3D 10 – 18
=3D –8        = ;            &n= bsp;          
Addition and Subtraction of Signed Numbers
The (   ), [   ], or {   } are grouping symbols. Eac= h set of symbol must contain both the left-hand and right-hand parts. Each set encloses calculations that are to be done within the symbol.
Example D :
a. –6 – (8 – 9)      do the calculation inside the “(  )”
=3D – 6 – (– 1)         remove parentheses
=3D – 6 + 1 
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9 &n= bsp;
=3D 10 – 18
=3D –8        = ;            &n= bsp;          
Addition and Subtraction of Signed Numbers
The (   ), [   ], or {   } are grouping symbols. Eac= h set of symbol must contain both the left-hand and right-hand parts. Each set encloses calculations that are to be done within the symbol.
Example D :
a. –6 – (8 – 9)      do the calculation inside the “(  )”
=3D – 6 – (– 1)         remove parentheses
=3D – 6 + 1 
=3D – 5
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9 &n= bsp;
=3D 10 – 18
=3D –8        = ;            &n= bsp;          
Addition and Subtraction of Signed Numbers
The (   ), [   ], or {   } are grouping symbols. Eac= h set of symbol must contain both the left-hand and right-hand parts. Each set encloses calculations that are to be done within the symbol.
Example D :
a. –6 – (8 – 9)      do the calculation inside the “(  )”
=3D – 6 – (– 1)         remove parentheses
=3D – 6 + 1 
=3D – 5
b. (–6 – 8) – 9     
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9 &n= bsp;
=3D 10 – 18
=3D –8        = ;            &n= bsp;          
Addition and Subtraction of Signed Numbers
The (   ), [   ], or {   } are grouping symbols. Eac= h set of symbol must contain both the left-hand and right-hand parts. Each set encloses calculations that are to be done within the symbol.
Example D :
a. –6 – (8 – 9)      do the calculation inside the “(  )”
=3D – 6 – (– 1)         remove parentheses
=3D – 6 + 1 
=3D – 5
b. (–6 – 8) – 9      do the calculation inside the “(  )”
=3D (–14) – 9        = ;  
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9 &n= bsp;
=3D 10 – 18
=3D –8        = ;            &n= bsp;          
Addition and Subtraction of Signed Numbers
The (   ), [   ], or {   } are grouping symbols. Eac= h set of symbol must contain both the left-hand and right-hand parts. Each set encloses calculations that are to be done within the symbol.
Example D :
a. –6 – (8 – 9)      do the calculation inside the “(  )”
=3D – 6 – (– 1)         remove parentheses
=3D – 6 + 1 
=3D – 5
b. (–6 – 8) – 9      do the calculation inside the “(  )”
=3D (–14) – 9        = ;    remove parentheses
=3D – 14 – 9
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b. 2 + (–4) – (–= 8) – (5) + (–9 )     remove the (  )’= s   
=3D 2 – 4 + 8 – 5 – 9       
=3D 2 + 8 – 4 – 5 – 9 &n= bsp;
=3D 10 – 18
=3D –8        = ;            &n= bsp;          
Addition and Subtraction of Signed Numbers
The (   ), [   ], or {   } are grouping symbols. Eac= h set of symbol must contain both the left-hand and right-hand parts. Each set encloses calculations that are to be done within the symbol.
Example D :
a. –6 – (8 – 9)      do the calculation inside the “(  )”
=3D – 6 – (– 1)         remove parentheses
=3D – 6 + 1 
=3D – 5
b. (–6 – 8) – 9      do the calculation inside the “(  )”
=3D (–14) – 9        = ;    remove parentheses
=3D – 14 – 9 =3D – 23
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Addition and Subtraction of Signed Numbers
If there is a set of grouping symbol inside another set of grouping = symbol, the inner set is to be calculated first.
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Addition and Subtraction of Signed Numbers
Example E :
   2 – [–6 –= (8 + 9)]      =
If there is a set of grouping symbol inside another set of grouping = symbol, the inner set is to be calculated first.
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Addition and Subtraction of Signed Numbers
Example E :
   2 – [–6 –= (8 + 9)]      = do the calculation inside the “(  )”
=3D 2 – [–6 – (17)]        = ; 
If there is a set of grouping symbol inside another set of grouping = symbol, the inner set is to be calculated first.
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Addition and Subtraction of Signed Numbers
Example E :
   2 – [–6 –= (8 + 9)]      = do the calculation inside the “(  )”
=3D 2 – [–6 – (17)]        = ;  remove parentheses
=3D 2 – [– 6 – 17]        = ;   
If there is a set of grouping symbol inside another set of grouping = symbol, the inner set is to be calculated first.
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Addition and Subtraction of Signed Numbers
Example E :
   2 – [–6 –= (8 + 9)]      = do the calculation inside the “(  )”
=3D 2 – [–6 – (17)]        = ;  remove parentheses
=3D 2 – [– 6 – 17]        = ;    do the calculation inside the “[   ]”
=3D 2 – [– 23]
If there is a set of grouping symbol inside another set of grouping = symbol, the inner set is to be calculated first.
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Addition and Subtraction of Signed Numbers
Example E :
   2 – [–6 –= (8 + 9)]      = do the calculation inside the “(  )”
=3D 2 – [–6 – (17)]        = ;  remove parentheses
=3D 2 – [– 6 – 17]        = ;    do the calculation inside the “[   ]”
=3D 2 – [– 23]
=3D 2 + 23
If there is a set of grouping symbol inside another set of grouping = symbol, the inner set is to be calculated first.
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Addition and Subtraction of Signed Numbers
Example E :
   2 – [–6 –= (8 + 9)]      = do the calculation inside the “(  )”
=3D 2 – [–6 – (17)]        = ;  remove parentheses
=3D 2 – [– 6 – 17]        = ;    do the calculation inside the “[   ]”
=3D 2 – [– 23]
=3D 2 + 23
=3D 25
If there is a set of grouping symbol inside another set of grouping = symbol, the inner set is to be calculated first.
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' + ENDSHOW_MESG + '

') doc.close() } function SetSldVisited(){ GetSldList().mList[gCurSld-1].mVisited=3Dtrue } function IsSldVisited(){ return GetSldList().mList[gCurSld-1].mVisited } function hrefList( sldHref, visible, advDelay, advClk ) { this.mSldHref=3D this.mNtsHref =3D sldHref this.mOrigVis=3D this.mVis =3D visible this.mVisited=3D false this.mAdvDelay=3D advDelay this.mAdvOnClk=3D advClk } function SldList(arr,curSld,fEnd) { this.mCurSld =3D curSld; this.mList =3D new Array(); var idx =3D 1; for(ii=3D0;ii 0) { PushSldList(sldList,fEnd); gCurSld =3D 1; } else if( PPTSld.event ) PPTSld.event.cancelBubble=3Dtrue } function PushSldList(arr,fEnd) { var ii =3D gSldStack.length; gSldStack[ii] =3D new SldList(arr,gCurSld,fEnd); GoToSld( gSldStack[ii].mList[0].mSldHref ); } function PopSldList() { if (gSldStack[gSldStack.length-1].fEndShow) EndShow() else { gCurSld =3D gSldStack[gSldStack.length-1].mCurSld; gSldStack[gSldStack.length-1] =3D null; gSldStack.length--; var sldList =3D gSldStack[gSldStack.length-1]; GoToSld( sldList.mList[gCurSld - 1].mSldHref ); } } var custShowList=3Dnew Array(); function ImgBtn( oId,bId,w,action ) { var t=3Dthis t.Perform =3D _IBP t.SetActive =3D _IBSetA t.SetInactive=3D _IBSetI t.SetPressed =3D _IBSetP t.SetDisabled=3D _IBSetD t.Enabled =3D _IBSetE t.ChangeIcon =3D null t.UserAction =3D action t.ChgState =3D _IBUI t.mObjId =3D oId t.mBorderId=3D bId t.mWidth =3D w t.mIsOn =3D t.mCurState =3D 0 } function _IBSetA() { if( this.mIsOn ) { obj=3Dthis.ChgState( gHiliteClr,gShadowClr,2 ) obj.style.posTop=3D0 } } function _IBSetI() { if( this.mIsOn ) { obj=3Dthis.ChgState( gFaceClr,gFaceClr,1 ) obj.style.posTop=3D0 } } function _IBSetP() { if( this.mIsOn ) { obj=3Dthis.ChgState( gShadowClr,gHiliteClr,2 ) obj.style.posLeft+=3D1; obj.style.posTop+=3D1 } } function _IBSetD() { obj=3Dthis.ChgState( gFaceClr,gFaceClr,0 ) obj.style.posTop=3D0 } function _IBSetE( state ) { var t=3Dthis GetObj( t.mBorderId ).style.visibility=3D"visible" if( state !=3D t.mIsOn ) { t.mIsOn=3Dstate if( state ) t.SetInactive() else t.SetDisabled() } } function _IBP() { var t=3Dthis if( t.mIsOn ) { if( t.UserAction !=3D null ) t.UserAction() if( t.ChangeIcon ) { obj=3DGetObj(t.mObjId) if( t.ChangeIcon() ) obj.style.posLeft=3Dobj.style.posLeft+(t.mCurState-4)*t.mWidth else obj.style.posLeft=3Dobj.style.posLeft+(t.mCurState-0)*t.mWidth } t.SetActive() } } function _IBUI( clr1,clr2,nextState ) { var t=3Dthis SetBorder( GetObj( t.mBorderId ),clr1,clr2 ) obj=3DGetObj( t.mObjId ) obj.style.posLeft=3Dobj.style.posLeft+(t.mCurState-nextState)*t.mWidth-obj= .style.posTop t.mCurState=3DnextState return obj } function TxtBtn( oId,oeId,action,chkState ) { var t=3Dthis t.Perform =3D _TBP t.SetActive =3D _TBSetA t.SetInactive=3D _TBSetI t.SetPressed =3D _TBSetP t.SetDisabled=3D _TBSetD t.SetEnabled =3D _TBSetE t.GetState =3D chkState t.UserAction =3D action t.ChgState =3D _TBUI t.mObjId =3D oId t.m_elementsId=3D oeId t.mIsOn =3D 1 } function _TBSetA() { var t=3Dthis if( t.mIsOn && !t.GetState() ) t.ChgState( gHiliteClr,gShadowClr,0,0 ) } function _TBSetI() { var t=3Dthis if( t.mIsOn && !t.GetState() ) t.ChgState( gFaceClr,gFaceClr,0,0 ) } function _TBSetP() { if( this.mIsOn ) this.ChgState( gShadowClr,gHiliteClr,1,1 ) } function _TBSetD() { this.ChgState( gFaceClr,gFaceClr,0,0 ) this.mIsOn =3D 0 } function _TBSetE() { var t=3Dthis if( !t.GetState() ) t.ChgState( gFaceClr,gFaceClr,0,0 ) else t.ChgState( gShadowClr,gHiliteClr,1,1 ) t.mIsOn =3D 1 } function _TBP() { var t=3Dthis if( t.mIsOn ) { if( t.UserAction !=3D null ) t.UserAction() if( !t.GetState ) return if( t.GetState() ) t.SetPressed() else t.SetActive() } } function _TBUI( clr1,clr2,lOffset,tOffset ) { SetBorder( GetObj( this.mObjId ),clr1,clr2 ) Offset( GetObj( this.m_elementsId ),lOffset,tOffset ) } function Offset( obj, top, left ){ obj.style.top=3Dtop; obj.style.left=3Dle= ft } function SetBorder( obj, upperLeft, lowerRight ) { s=3Dobj.style; s.borderStyle =3D "solid" s.borderWidth =3D 1 s.borderLeftColor =3D s.borderTopColor =3D upperLeft s.borderBottomColor=3D s.borderRightColor =3D lowerRight } function GetBtnObj(){ return gBtnArr[window.event.srcElement.id] } function BtnOnOver(){ b=3DGetBtnObj(); if( b !=3D null ) b.SetActive() } function BtnOnDown(){ b=3DGetBtnObj(); if( b !=3D null ) b.SetPressed() } function BtnOnOut(){ b=3DGetBtnObj(); if( b !=3D null ) b.SetInactive() } function BtnOnUp() { b=3DGetBtnObj() if( b !=3D null ) b.Perform() else Upd() } function GetNtsState(){ return parent.gNtsOpen } function GetOtlState(){ return parent.gOtlOpen } function GetOtlTxtState(){ return parent.gOtlTxtExp } function NtsBtnSetFlag( fVal ) { s=3Ddocument.all.item( this.m_flagId ).style s.display=3D"none" if( fVal ) s.display=3D"" else s.display=3D"none" } function _BSetA_Border(){ b =3D gBtnArr[this.mObjId]; if( b !=3D null ) b.S= etActive() } function _BSetI_Border(){ b =3D gBtnArr[this.mObjId]; if( b !=3D null ) b.S= etInactive() } var gHiliteClr=3D"THREEDHIGHLIGHT",gShadowClr=3D"THREEDSHADOW",gFaceClr=3D"= THREEDFACE" var gBtnArr =3D new Array() gBtnArr["nb_otl"] =3D new TxtBtn( "nb_otl","nb_otlElem",parent.ToggleOtlPan= e,GetOtlState ) gBtnArr["nb_otlElem"] =3D new TxtBtn( "nb_otl","nb_otlElem",parent.ToggleOt= lPane,GetOtlState ) gBtnArr["nb_nts"] =3D new TxtBtn( "nb_nts","nb_ntsElem",parent.ToggleNtsPan= e,GetNtsState ) gBtnArr["nb_prev"]=3D new ImgBtn( "nb_prev","nb_prevBorder",30,parent.GoToP= revSld ) gBtnArr["nb_next"]=3D new ImgBtn( "nb_next","nb_nextBorder",30,parent.GoToN= extSld ) gBtnArr["nb_sldshw"]=3D new ImgBtn( "nb_sldshw","nb_sldshwBorder",18,parent= .FullScreen ) gBtnArr["nb_sldshwBorder"] =3D new TxtBtn( "nb_sldshw","nb_sldshwBorder",pa= rent.FullScreen,null ) gBtnArr["nb_sldshwBorder"].SetActive =3D _BSetA_Border; gBtnArr["nb_sldshwBorder"].SetInactive =3D _BSetI_Border; gBtnArr["nb_sldshwText"] =3D new TxtBtn( "nb_sldshw","nb_sldshwText",parent= .FullScreen,null ) gBtnArr["nb_sldshwText"].SetActive =3D _BSetA_Border; gBtnArr["nb_sldshwText"].SetInactive =3D _BSetI_Border; gBtnArr["nb_voice"] =3D new ImgBtn( "nb_voice","nb_voiceBorder",18,parent.= ToggleVNarration ) gBtnArr["nb_otlTxt"]=3D new ImgBtn( "nb_otlTxt","nb_otlTxtBorder",23,parent= .ToggleOtlText ) gBtnArr["nb_nts"].m_flagId=3D "notes_flag" gBtnArr["nb_nts"].SetFlag =3D NtsBtnSetFlag gBtnArr["nb_otlTxt"].ChangeIcon=3D GetOtlTxtState var sNext=3D"Next",sPrev=3D"Previous",sEnd=3D"End Show",sFont=3D"Arial",sAr= row=3D"Arrow",sFreeform=3D"Freeform",sRect=3D"Rectangle",sOval=3D"Oval" function ShowMenu() { BuildMenu(); var doc=3DPPTSld.document.body,x=3DPPTSld.event.clientX+doc.scrollLeft,y= =3DPPTSld.event.clientY+doc.scrollTop m =3D PPTSld.document.all.item("ctxtmenu") m.style.pixelLeft=3Dx if( (x+m.scrollWidth > doc.clientWidth)&&(x-m.scrollWidth > 0) ) m.style.pixelLeft=3Dx-m.scrollWidth m.style.pixelTop=3Dy if( (y+m.scrollHeight > doc.clientHeight)&&(y-m.scrollHeight > 0) ) m.style.pixelTop=3Dy-m.scrollHeight m.style.display=3D"" } function _CM() { if( !parent.IsFullScrMode() ) return; if(!PPTSld.event.ctrlKey) { ShowMenu() return false } else HideMenu() } function BuildMenu() { if( PPTSld.document.all.item("ctxtmenu") ) return var mObj=3DCreateItem( PPTSld.document.body ) mObj.id=3D"ctxtmenu" mObj.style.visibility=3D"hidden" var s=3DmObj.style s.position=3D"absolute" s.cursor=3D"default" s.width=3D"120px" SetCMBorder(mObj,"menu","black") var iObj=3DCreateItem( mObj ) SetCMBorder( iObj, "threedhighlight","threedshadow" ) iObj.style.padding=3D2 CreateMenuItem( iObj,sNext,M_GoNextSld,M_True ) CreateMenuItem( iObj,sPrev,M_GoPrevSld,M_HasPrevSld ) CreateSeparator( iObj ) CreateMenuItem( iObj,sEnd,M_End,M_True ) mObj.style.visibility=3D"visible" } function Cancel() { window.event.cancelBubble=3Dtrue; window.event.returnVa= lue=3Dfalse } function Highlight() { ChangeClr("activecaption","threedhighlight") } function Deselect() { ChangeClr("threedface","menutext") } function Perform() { e=3DPPTSld.event.srcElement if( e.type=3D=3D"menuitem" && e.IsActive() ) e.Action() else PPTSld.event.cancelBubble=3Dtrue } function ChangeClr( bg,clr ) { e=3DPPTSld.event.srcElement if( e.type=3D=3D"menuitem" && e.IsActive() ) { e.style.backgroundColor=3Dbg e.style.color=3Dclr } } function M_HasPrevSld() { return( parent.HasPrevSld() ) } function M_GoNextSld() { if( gIsEndShow ) M_End(); else GoToNextSld() } function M_GoPrevSld() { if( gIsEndShow ) { history.back(); PPTSld.event.ca= ncelBubble=3Dtrue; } else GoToPrevSld() } function M_True() { return true } function M_End() { window.close( self ) } function CreateMenuItem( node,text,action,eval ) { var e=3DCreateItem( node ) e.type=3D"menuitem" e.Action=3Daction e.IsActive=3Deval e.innerHTML=3Dtext if( !e.IsActive() ) e.style.color=3D"threedshadow" e.onclick=3DPerform e.onmouseover=3DHighlight e.onmouseout=3DDeselect s=3De.style; s.fontFamily=3DsFont s.fontSize=3D"9pt" s.paddingLeft=3D2 } function CreateSeparator( node ) { var sObj=3DCreateItem( node ) SetCMBorder(sObj,"menu","menu") var s=3DsObj.style s.borderTopColor=3D"threedshadow" s.borderBottomColor=3D"threedhighlight" s.height=3D1 s.fontSize=3D"0px" } function CreateItem( node ) { var elem=3DPPTSld.document.createElement("DIV") node.insertBefore( elem ) return elem } function SetCMBorder( o,ltClr,rbClr ) { var s=3Do.style s.backgroundColor=3D"menu" s.borderStyle=3D"solid" s.borderWidth=3D1 s.borderColor=3DltClr+" "+rbClr+" "+rbClr+" "+ltClr } ------=_NextPart_01C8D7F8.DB4BAC50 Content-Location: file:///C:/7102A2B3/2AdditionandSubtractionofSignedNumbers_files/fullscreen.htm Content-Transfer-Encoding: quoted-printable Content-Type: text/html; 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charset="us-ascii" Addition and Subtraction of Signed Numbers ------=_NextPart_01C8D7F8.DB4BAC50 Content-Location: file:///C:/7102A2B3/2AdditionandSubtractionofSignedNumbers_files/outline.htm Content-Transfer-Encoding: quoted-printable Content-Type: text/html; charset="us-ascii"
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